12x^2+16=3

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Solution for 12x^2+16=3 equation: 



12x^2+16=3

We move all terms to the left:

12x^2+16-(3)=0

We add all the numbers together, and all the variables

12x^2+13=0

a = 12; b = 0; c = +13;
Δ = b2-4ac
Δ = 02-4·12·13
Δ = -624
Delta is less than zero, so there is no solution for the equation

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